1.

The system shown in the figure is in equilibrium, where A and B are isomeric liquids and form an ideal solution at TK. Standard vapour pressures of A and B are P_(A)^(0) and P_(B)^(0), respectively, at TK. We collect the vapour of A and B in two containers of volume V, first container is maintained at 2 T K and second container is maintained at 3T//2. At the temperature greater than T K, both A and B exist in only gaseous form. We assume than collected gases behave ideally at 2 T K and there may take place an isomerisation reaction in which A gets converted into B by first-order kinetics reaction given as: Aoverset(k)rarrB, where k is a rate constant. In container (II) at the given temperature 3T//2, A and B are ideal in nature and non reacting in nature. A small pin hole is made into container. We can determine the initial rate of effusion of both gases in vacuum by the expression r=K.(P)/(sqrt(M_(0))) where P= pressure differences between system and surrounding K= positive constant M_(0)= molecular weight of the gas Vapours of A and B are passed into a container of volume 8.21 L, maintained at 2T K, where T=50 K and after 5 min, moles of B=8//3. The pressure developed into the cotainer after two half lives is

Answer»

`3 ATM`
`4 atm`
`5 atm`
`0.5 atm`

Solution :`(n_(A))/(n_(B))=(2)/(1)`
`UNDERSET(8//3)(A)overset(K)rarrunderset(4//3)(B)`
`t=5 min (8)/(3)-x (4)/(3)+x=(8)/(3)impliesx=(4)/(3)`
`=4//3implies t=t_(1//2)=5 min`
`implies` At `t=10 min underset(x//3)(A)overset(K)rarrunderset(10//3)(B)`
`implies P=(4xx0.0821xx100)/(8.21)=4 atm`


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