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The tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Then the length of the tangent is(A) 13 cm(B) \(\sqrt{119}\)(C) 14 cm(D) 11 cm |
Answer» Correct option is: (B) \(\sqrt{119}\) cm. \(\because\) OP \(\perp\) PQ (Radius and tangent are perpendicular at point of contact) = \(\angle\) OPQ = 90° Now, in right \(\triangle\) OPQ \(PQ^2 = OQ^2 - OP^2 = 12^2 - 5^2 \) = 144 - 25 = 119 \(\therefore\) PQ = \(\sqrt{119}\) cm Hence, length of tangent PQ is \(\sqrt{119}\) cm. Correct option is: (B) \(\sqrt{119}\) |
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