InterviewSolution
Saved Bookmarks
| 1. |
The tangent to curve y_(1)=ax^(2)+bx+7/2 at (1,2)is parallel to normal at point (-2,2) on curve y_(2)=x^(2)+6x+10 then value of (a-2b) is |
|
Answer» `2=a+b+7/2impliesa+b=-3/2`……………1 `((dy_(1))/(dx))_((1,2))=-1/(((dy_(2))/(dx))_((-2,2)))` `2a+b=-1/2` |
|