1.

The tangent to curve y_(1)=ax^(2)+bx+7/2 at (1,2)is parallel to normal at point (-2,2) on curve y_(2)=x^(2)+6x+10 then value of (a-2b) is

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Solution :(1,2) LIES on `y_(1)`
`2=a+b+7/2impliesa+b=-3/2`……………1
`((dy_(1))/(dx))_((1,2))=-1/(((dy_(2))/(dx))_((-2,2)))`
`2a+b=-1/2` `a-2b=6`


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