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The tangents from `(1, 2sqrt2)` to the hyperbola `16x^2-25y^2 = 400` include between them an angle equal to:A. `(pi)/6`B. `(pi)/4`C. `(pi)/3`D. `(pi)/2` |
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Answer» Correct Answer - D `(1,2sqrt(2))` lies on director circle or `(x^(2))/25-(y^(2))/16=1` i.e. `x^(2)+y^(2)=9` `:.` Required angle `pi//2` |
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