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The taxi charges in a city comprise of a fixed charge of Rs 100 for 5 kms and Rs 16 per km for ever additional km. If the amount paid at the end of the trip was Rs 740, find the distance traveled. |
Answer» Let the distance travelled by taxi be ‘x’ km For the first 5 km the charge = Rs 100 For additional kms the charge = Rs 16(x – 5) ∴ For x kms the charge = 100 + 16(x – 5) Amount paid = Rs 740 ∴ 100 + 16(x – 5) = 740 100 + 16(x – 5) – 100 = 740- 100 16(x – 5) = 640 \(\frac{16(x-5)}{16}=\frac{640}{16}\) x – 5 = 40 x – 5 + 5 = 45 + 5 x = 45 x = 45 km ∴ Total distance travelled = 45 km |
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