1.

The taxi charges in a city comprise of a fixed charge of Rs 100 for 5 kms and Rs 16 per km for ever additional km. If the amount paid at the end of the trip was Rs 740, find the distance traveled.

Answer»

Let the distance travelled by taxi be ‘x’ km 

For the first 5 km the charge = Rs 100 

For additional kms the charge = Rs 16(x – 5) 

∴ For x kms the charge = 100 + 16(x – 5) 

Amount paid = Rs 740 

∴ 100 + 16(x – 5) = 740 

100 + 16(x – 5) – 100 = 740- 100 

16(x – 5) = 640

\(\frac{16(x-5)}{16}=\frac{640}{16}\)

x – 5 = 40 

x – 5 + 5 = 45 + 5 

x = 45 

x = 45 km 

∴ Total distance travelled = 45 km



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