1.

The teacher tells the students in the class that the highest marks obtained by a student in the class is 7 more than twice the lowest marks. If the highest mark is 93, then what is the lowest mark ?

Answer»

Let the lowest mark = x 

then the highest mark twice the lowest mark + 7 = 93 

⇒ 2x + 7 = 93 

⇒ 2x + 7 – 7 = 93 – 7 (Subtract 7 on both side) 

⇒ 2x = 86

⇒ 2x/2 = 86/2 (Divide by 2 on both sides)

⇒ x = 43 

∴ Lowest mark = 43



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