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The teacher tells the students in the class that the highest marks obtained by a student in the class is 7 more than twice the lowest marks. If the highest mark is 93, then what is the lowest mark ? |
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Answer» Let the lowest mark = x then the highest mark twice the lowest mark + 7 = 93 ⇒ 2x + 7 = 93 ⇒ 2x + 7 – 7 = 93 – 7 (Subtract 7 on both side) ⇒ 2x = 86 ⇒ 2x/2 = 86/2 (Divide by 2 on both sides) ⇒ x = 43 ∴ Lowest mark = 43 |
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