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The temperature at which `K_(c) and K_(p)` will have the same value for the equilibrium , ` N_(2) O_(4) (g) hArr 2 NO_(2) (g) ` isA. 0 KB. 273 KC. 1 KD. 12.18 K |
Answer» Correct Answer - D ` K_(p) = K_(c) (RT)^(Delta n_(g)). " Here" , Delta n _(g) = 2-1 = 1. " Hence " ,` ` i.e. T= 1/R = 1/(0*0821)= 12*18 K` |
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