The temperature inside a refrigerator is t_(2)^(@)C . The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be

The temperature inside a refrigerator is t_(2)^(@)C . The amount of he

1.	The temperature inside a refrigerator is t_(2)^(@)C . The amount of heat delivered to the room for each joule of electrical energy consumed ideally will be
Answer» `(t_(1))/(t_(1)-t_(2))` `(t_(1)+273)/(t_(1)-t_(2))` `(t_(2)+273)/(t_(1)-t_(2))` `(t_(1)+t_(2))/(t_(1)+273)` Solution :Temperature inside refrigeratior =`t_(2)^(@)C` Room temperature = `t_(1)^(@)C` For refrigerator, `(" HEAT given to high temperature" (Q_(1)))/("Heat taken from lower temperature" (Q_(2)))=(T_(1))/(T_(2))` `(Q_(1))/(Q_(2))=(t_(1)+273)/(t_(2)+273)` `RARR (Q_(1)/(Q_(1)-W)=(t_(1)+273)/(t_(2)+273)` or , `1-(W)/(Q_(1))=(t_(2)+273)/(t_(1)+273)` or `(W)/(Q_(1))=(t_(1)-t_(2))/(t_(1)+273)` The amount of HET delivered to the room for each joule of electrical energy (W=1 J) `Q_(1)=(t_(1)+273)/(t_(1)-t_(2))`