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The temperature of 2 moles ofan ideal gas is raisedfrom 27^(@)Cto 77^(@)C. What is the value forDeltaH - DeltaU for the process ? ( R= 8.3 J K^(-1)mol^(-1)) |
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Answer» 415J `:. H_(2)-H_(1) = ( U_(2)+nRT_(2)) - ( U_(1)+nRT_(1)) ` `= ( U_(2)-U_(1))+nRT(T_(2)-T_(1))` or `DeltaH = DeltaU + nR DELTAT` or `DeltaH- DeltaU = nRT = 2 XX 8.3 xx 50 = 830 J` |
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