The temperature of 5 moles of a gas is decreased by 2K at constant pressure of 1 atm. Indicate the correct statement

The temperature of 5 moles of a gas is decreased by 2K at constant pre

1.	The temperature of 5 moles of a gas is decreased by 2K at constant pressure of 1 atm. Indicate the correct statement
Answer» <P>Work done by GAS is = 5R Work done on the gas is = 10R Work done by the gas = 6R Work done = 0 Solution :For 5 moles of gas at temperature T, `pv_(1) = 5RT` For 5 moles of gas at temperature T-2 `PV_(2) = 5R (T-2)` `:. P(V_(2) - V_(1)) = 5R (T-2-T), P DELTA V = -10R, - P Delta V = 10R` When `DeltaV= 10R` When `Delta V` is negative, W is +ve