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The temperature of a given mass of air was changed from `15^(@)C` to `-15^(@)C`. If the pressure remains unchanged and the initial volume was `100 mL`, what should be the final volume? |
Answer» Given `T_(1)=15^(@)C` or `15+273.15 K=288.15 K` `V_(1)=100 mL` `T_(2)= -15^(@)C=273.15-15=258.15 K` `V_(2)=?` We know `(V_(1))/(T_(1))=(V_(2))/(T_(2))` ` :. V_(2)=(V_(1))/(T_(1))xxT_(2)=(100xx258.15)/(288.15)=89.58 mL` |
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