1.

The temperature of a physical pendulum, whose time period is T, is raised by Deltatheta. The change in its time period is

Answer»

`1/2 alphaDelta theta`
`2alphe T DELTA theta`
`1/2 alpha Delta theta`
2 alpha Delata theta`

Solution : `T=2pisqrt(1/g)rArr Tprop sqrtl`
`THEREFORE""(T')/T=((L')/l)^(2)=1+1/2(DELTAL)/l=1+1/2alphaDeltatheta`
`therefore""Delta T T'-T=1/2alpha Delta theta


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