1.

The temperature of an idea gas is increased from 120 K to 480 K. If at 120 K the root mean square velocity of the gas molecules is nu, at 480 K it becomes

Answer»

`77^(@)C`<BR>`350^(@)`
`273^(@)C`
`457^(@)C`

SOLUTION :Let the REQUIRED temperature br T. Then
`(3RT)/28=(3R(273+127))/32=impliesT350K=77^(@)C`


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