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The temperature of an ideal gas is increased from 120K to 480K. If at 120K the root-mean-squre velocity of the gas molecules is v, at 480K it becomesA. `4v`B. `2v`C. `v//2`D. `v//4` |
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Answer» Correct Answer - B `v_("rms")=sqrt((3RT)/(M))` `v_("rms")propsqrt(T)` When temperature is increased from `120K` to `480K` (i.e., four times), the root mean square speed will become `sqrt(4)` or `2` times, `i.e., `2v` . |
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