The temperature of an isolated black body falls from T_(1) to T_(2) in time t. Let c be a constant

The temperature of an isolated black body falls from T_(1) to T_(2) in

1.	The temperature of an isolated black body falls from T_(1) to T_(2) in time t. Let c be a constant
Answer» `t = c [(1)/(T_(2)) - (1)/(T_(1))]` `t = c [(1)/(T_(2)^(3)) - (1)/(T_(1)^(2))]` `t = c [(1)/(T_(2)^(3)) - (1)/(T_(1)^(3))]` `t = c [(1)/(T_(2)^(4)) - (1)/(T_(1)^(4))]` Solution :(3) `ms (dT)/(dt) = - SIGAM A (T^(4) - 0)` `int_(T_(1))^(T_(2)) (dT)/(T^(4)) = - sigma A int_(0)^(t) dt` `[(1)/(T_(2)^(3)) - (1)/(T_(1)^(3))] = (3 sigma A) t` `t - (1)/((3 sigma A)) [(1)/(T_(2)^(3)) - (1)/(R_(1)^(3))]` `t = c [(1)/(T_(2)^(3)) - (1)/(T_(1)^(3))], c = (1)/(3 sigma A)`