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The temperature of the gas is raised from `27^(@)C` to `927^(@)C`, the root mean square velocity isA. `sqrt((927)/(27))` times of the earlier valueB. same as beforeC. halvedD. doubled |
Answer» Correct Answer - D Root mean square velocity at `T_(1)` temperature, `U_(1)=sqrt((3RT_(2))/(M))=sqrt((3R(27+273))/(M))" ...(i)"` Root mean square velocity at `T_(2)` temperature, `U_(2)=sqrt((3RT_(2))/(M))=sqrt((3R(927+273))/(M))" ...(ii)"` Eq. (i) divided by Eq. (ii) `(U_(1))/(U_(2))=sqrt((27+273)/(927+273))=sqrt((300)/(1200))=(1)/(2)` `U_(2)=2U_(1)` |
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