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The temperature of two bodies measured by a thermometer are `t_1=20^@C pm 0.5^@C ` and `t_2=50^@C pm 0.5^@C` . Calculate the temperature difference and error there in .A. `30^(@)C+-1^(@)C`B. `70^(@)C+-0.5^(@)C`C. `30^(@)C+-0.5^@C`D. `70^(@)C+-1^(@)C` |
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Answer» Correct Answer - A Here, `t_(1)=20^(@)C+-0.5^(@)C,t_(2)=50^(@)C+-0.5^(@)C` The temperature difference of two bodies is `t=t_(2)-t_(1)=50^(@)C-20^(@)C=30^(@)C` the error in temperature difference of two bodies is `Deltat=(Deltat_(1)+Deltat_(2))=(0.5^(@)C+0.5^(@)C)=1^(@)C` `therefore` The temperature difference is `30^(@)C+-1^(@)C`. |
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