1.

The temperature on the new scale, corresponding to a temperature of 39^(@)C on the celsius scale?

Answer»

`73^(@)W`
`117^(@)W`
`200^(@)W`
`139^(@)W`

Solution :Let t be the REQUIRED temperature. Then,
`(t-39)/(239-39)=(39-0)/(100-0)RARR t = 117^(@)W`


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