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The terminal velocity of a copper ball of radius `2mm` falling through a tank of oil at `20^(@)C` is `6.5cm//s`. Find the viscosity of the oil at `20^(@)C`. Density of oil is `1.5xx10^(3)Kg//m^(3)`, density of copper is `8.9xx10^(3)Kg//m^(3)`. |
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Answer» We have `v_(t)=6.5xx10^(-2)ms^(-1),a=2xx10^(-3)m`. `g=9.8ms^(-2),rho=8.9xx10^(3)kgm^(-3)` `sigma=1.5xx10^(3)kgm^(-3)`. From Eq. `eta=(2)/(9)xx((2xx10^(-3))^(2)m^(2)xx9.8ms^(-2))/(6.5xx10^(-2)ms^(-1))xx7.4xx10^(3)kgm^(-3)` `=9.9xx10^(-1)kgm^(-1)s^(-1)` |
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