1.

The terminal velocity of a tiny droplet is v. N number of such identical droplets combine together forming a bigger drop. Find the terminal velocity of the bigger drop.

Answer»

Solution :`nu=(2)/(9)[(g(sigma-rho)r^(2))/eta]`
`implies "" (nu)/(r^(2))=(2g)/(9eta)(sigma-rho)"" CDOTS(1)`
Similarly , `"" (nu)/(R^(2))=(2g)/(9eta)(sigma-rho)"" cdots(2)`
`(nu)/(nu)=(r^(2))/(R^(2))impliesv=nu((R)/(r))^(2)`
If N drops coalesce, then VOLUME of one big drop = Volume of N droplets
`(4)/(3)piR^(3)= N((4)/(3)pir^(3))`
R `"" =N^(1//3)r`
`:.` Terminal velocity of bigger drop
`=((R)/(r))^(2) XXV` from equation (1)
`=N^(2//3) nu` from equation (2)


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