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The terminal velocity of a tiny droplet is v. N number of such identical droplets combine together forming a bigger drop. Find the terminal velocity of the bigger drop. |
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Answer» Solution :`nu=(2)/(9)[(g(sigma-rho)r^(2))/eta]` `implies "" (nu)/(r^(2))=(2g)/(9eta)(sigma-rho)"" CDOTS(1)` Similarly , `"" (nu)/(R^(2))=(2g)/(9eta)(sigma-rho)"" cdots(2)` `(nu)/(nu)=(r^(2))/(R^(2))impliesv=nu((R)/(r))^(2)` If N drops coalesce, then VOLUME of one big drop = Volume of N droplets `(4)/(3)piR^(3)= N((4)/(3)pir^(3))` R `"" =N^(1//3)r` `:.` Terminal velocity of bigger drop `=((R)/(r))^(2) XXV` from equation (1) `=N^(2//3) nu` from equation (2) |
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