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The thermo e.m.f. E in volts of a certain thermocouple is found to vary with temperature difference q in `.^(@)C` between the two junctions according to the relation `E=30 theta-(theta^(2))/(15)` The neutral temperature for the thermo-couple will be:-A. `400^(@)C`B. `225^ (@)C`C. `30^(@)C`D. `450^(@)C` |
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Answer» At neutral temperature `(dE)/(dtheta)=0` so `30-(2thetan)/(15) =0rArrtheta_(n)=225^(@)C` |
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