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The thermo emf E of a thermocouple is found to vary wit temperature T of the junction (cold junction is `0^(@)C`) as `E=40T-(T^(2))/(20)` The temperature of inversion for the thermocouple isA. `200^(@)C `B. `400^(@)C`C. `800^(@)C`D. `1000^(@)C` |
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Answer» The temperature of inversion `T_(i)=2T_(n)-_(c)` whre `T_(c)=0^(@)C ` and `T_(n)` is netural temperature. At `T_(n) ,(dE)/(dt)=0` `therefore E=40T-(T^(2))/(20)rArr(dE)/(dt)=40-(2T)/(20)` or `0 =40-(2T_(n))/(20)rArr T_(n)=400^(@)C` `therefore T_(i)=2T_(n)-T_(c)` `=(2xx400)-0=800^(@)C` |
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