The thickness of ice on a Jake is 6 cm and the temperature of air is - 10^(@) C. At what rate is the thickness of ice increasing ? Thermal conductivity of ice = 2 "Wm"^(-1) "K"^(-1). Density of ice = 920 "kg m"^(3), specific latent heat of ice = 336 "KJ kg"^(-1)

The thickness of ice on a Jake is 6 cm and the temperature of air is -

1.	The thickness of ice on a Jake is 6 cm and the temperature of air is - 10^(@) C. At what rate is the thickness of ice increasing ? Thermal conductivity of ice = 2 "Wm"^(-1) "K"^(-1). Density of ice = 920 "kg m"^(3), specific latent heat of ice = 336 "KJ kg"^(-1)
Answer» Solution :`dx// DT = K ( theta_2 - theta_1 ) // x rho L = 2(10)//6 xx 10^(-2)xx 920 xx 336 xx 10^(3) - 10^(-6) "MS"^(-1)`