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| 1. |
The third line in Balmer series corresponds to an electronic transfer between which Bohr's orbit in hydrogen A.5to3 B.5to2 C.4to3 D.4to2 |
| Answer» SINCE, the inner orbit is 2 and from the given question we get to KNOW that transition is REQUIRED for the third line of BALMER series hence the outer orbit must be n2=2+3 = 5. Thus, the transition must be from 2 to 5. | |