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The third term of a geometric progression with common ratio equal to half the initial term is 81. Determine the 12^th term.(a) 3^12(b) 4^15(c) 6^8(d) 5^9I got this question in an internship interview.Query is from Discrete Probability in portion Discrete Probability of Discrete Mathematics

Answer» RIGHT choice is (a) 3^12

The best EXPLANATION: Let the initial term be a and the COMMON RATIO r. The 3^rd term is ar^2 = 27 and the initial term is a=3r so 3r^3 = 81⇒ r=3 ⇒ a=3. The a12 = a * r^11 = 3 * 3^11 = 3^12.


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