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The threshold frequency for a metal is 7.0 xx 10^(14) s^(-1). Calculate the kinetic energy of an electron emitted when radiation of frequency 10^(15)s^(-1) hits the metal. |
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Answer» Solution :`KE=h(v-v_(0))=` `(6.625xx10^(-34))/(1.0xx10^(15)-7.0xx10^(14))` `=1.988xx10^(-19)J` |
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