1.

The threshold frequency for a metal is 7.0 xx 10^(14) s^(-1). Calculate the kinetic energy of an electron emitted when radiation of frequency 10^(15)s^(-1) hits the metal.

Answer»

Solution :`KE=h(v-v_(0))=`
`(6.625xx10^(-34))/(1.0xx10^(15)-7.0xx10^(14))`
`=1.988xx10^(-19)J`


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