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| 1. |
The threshold frequency V_0 for a metal is 7.0xx10^14 s^1. Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0xx10^15s^(-1) hits the metal. |
| Answer» Solution :ACCORDING to Einstein’s equation Kinetic energy `=1//2m_eV^2=h(v-v_0)=(6.626xx10^(-34)Js)XX(1.0xx10^15s^-1-7.0xx10^14s^-1)=(6.626xx10^(-34)Js)xx(10.0xx10^14s^-1-7.0xx10^14s^-1)=(6.626xx10^(-34)Js)xx(3.0xx10^14s^-1)=1.988xx10^(-19)J` | |