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The threshold frequency v_(0) for a metal is 7xx10^(14)s^(-1) . Calculate the kinetic energy of an electron emitted when radiation of frequency v = 1.0 xx 10^(15)s^(-1) hits the metal . |
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Answer» SOLUTION :According to EINSTEIN's equation, K.E. of the photoelectron emitted `((1)/(2) mv^(2))` `= h (v - v_(0)) = (6.626 xx 10^(-34) Js) (1.0 xx 10^(15) s^(-1) - 7.0 xx 10^(14) s^(-1))` `= (6.626 xx 10^(-34)Js) (3 xx 10^(14) s^(-1)) = 19.88 xx 10^(-20) J or 1.988 xx 10^(-19) J` |
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