1.

The time in seconds taken for 20 oscillations noted down in an simple pendulum experiment are 38.6, 40.0, 41.5, 42.8 and 39.4, the time period of the given simple pendulum is ____ s

Answer»

`2.5`
`2.2`
`2.0`
`10.1`

SOLUTION :`T = (38.6 + 40 + 41.5 + 42.8 + 39.4)/((5)/(20))`
`= 2.023s ~~ 2S`


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