1.

The time of completion of 90% of a first order reaction is approximately

Answer»

1.1 TIMES that of half-LIFE
2.2 times that of half-life
3.3 times that of half - life
4.4 times that of half-life

SOLUTION :For a first order reaction
`k = (2.303)/(t)"log" (a)/((a-x))`
` t = (2.303)/(k) "log" (100)/((100 - 90)) = (2.303 XX t_(1//2))/(0.593) xx "log" (100)/(10)`
`= 3.3 xx t_(1//2) xx "log" 10 = 3.3 t_(1//2)`.


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