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The time of vibration of a dip needle vibration in the vertical plane in the magnetic needle is made to vibrate in the horizontal plane, the time of vibration is `3sqrt2 s`. Then angle of dip will be-A. `90^(@)`B. `60^(@)`C. `45^(@)`D. `30^(@)` |
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Answer» Correct Answer - B In magnetic meridian `3 = 2pi sqrt((I)/(MB_(e))) …(1)` In horizontal plane, `3 sqrt(2) = 2pi sqrt((I)/(MH)) …(2)` `therefore (3)/(3sqrt(2)) = sqrt((H)/(B_(e))) = sqrt((B_(e) costheta)/(B_(e))) rArr 0 = 60^(@)` |
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