1.

The time period of a satellite of earth is 5 hr. If the seperation between the earth and satellite is increased to 4 times the previous value the new time period will become ....

Answer»

10 hr
80 hr
40 hr
20 hr

Solution :`implies` ACCORDING to `T^(2) alpha r^3`
`T_2^2/T_1^2=r_1^3/r_1^3`
`:. T_1^2/(25)=((4R)/r)^3`
`T_2^2 = 25 xx 64 `
`:. T_2= 5xx 8 `
`:. T_2 = 40 hr `


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