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The time period of a satellite of earth is 5 hr. If the seperation between the earth and satellite is increased to 4 times the previous value the new time period will become .... |
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Answer» 10 hr `T_2^2/T_1^2=r_1^3/r_1^3` `:. T_1^2/(25)=((4R)/r)^3` `T_2^2 = 25 xx 64 ` `:. T_2= 5xx 8 ` `:. T_2 = 40 hr ` |
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