The time -period of a simple pendulum is 2s and its can go to and fro from equilibrium position at a maximum distance of 5 cm. if at the start of the motion the pendulum is the position of maximum displacements towars the right of the equilibrium position, then write the displacement equation of the pendulum.

The time -period of a simple pendulum is 2s and its can go to and fro

1.	The time -period of a simple pendulum is 2s and its can go to and fro from equilibrium position at a maximum distance of 5 cm. if at the start of the motion the pendulum is the position of maximum displacements towars the right of the equilibrium position, then write the displacement equation of the pendulum.
Answer» Solution :The displacement in SHM is given by `y=A SIN (omegat+phi_(0))` Given `T=2s, A=5 CM` `omega=(2pi)/(T)=(2pi)/(2)= pi "rad" s^(-1)` `:.y=5 sin (pixx0+phi_(0))` (or)`sin phi_(0)=1 rArr :. Phi_(0)=(pi)/(2)` Hence displacement equation for the pendulum is `y= 5 sin (pi +(pi)/(2))= 5 cost. `