The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) – InterviewSolution

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1.	The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place. (a) Express 'g' in terms of T (b) What is the length of the seconds pendulum ? (Take g = 10 m s^(-2))
Answer» Solution :(i) `T = 2pi sqrt((l)/(g))` (1) Square EQUATION (1) on both the SIDES write g in TERM of 'l' and ''T''. (ii) 101 CM

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