1.

The time period of oscillation of a particle that executes `SHM` is `1.2s`. The time starting from mean position at which its velocity will be half of its velocity at mean position isA. `0.1s`B. `0.2s`C. `0.4s`D. `0.6s`

Answer» Correct Answer - A
`V = (V_(max))/(2) rArr x =+-(sqrt(3)A)/(2), x = A cos ((2pi)/(T)t)`


Discussion

No Comment Found

Related InterviewSolutions