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The time period of oscillation of a particle that executes `SHM` is `1.2s`. The time starting from mean position at which its velocity will be half of its velocity at mean position isA. `0.1s`B. `0.2s`C. `0.4s`D. `0.6s` |
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Answer» Correct Answer - A `V = (V_(max))/(2) rArr x =+-(sqrt(3)A)/(2), x = A cos ((2pi)/(T)t)` |
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