1.

The time period of oscillation of a `SHO` is `(pi)/(2)s`. Its acceleration at a phase angle `(pi)/(3) rad` from exterme position is `2ms^(-1)`. What is its velocity at a displacement equal to half of its amplitude form mean position? (in `ms^(-1)`A. `0.707`B. `0.866`C. `sqrt(2)`D. `sqrt(3)`

Answer» Correct Answer - C
`V = omega sqrt(A^(2) - x^(2)), a = omega^(2)x`


Discussion

No Comment Found

Related InterviewSolutions