1.

The time period of simple pendulum is T. When the length increases by 10 cm , its peirod is T_(1). When the length is decreased by 10 cm, its period is T_(2). Then the relation between T, T_(1) and T_(2) is

Answer»

`2/(T^(2))=1/(T_(1)^(2))+1/(T_(2)^(2))`
`2/(T^(2))=1/(T_(1)^(2))-1/(T_(2)^(2))`
`2T^(2)=T_(1)^(2)+T_(2)^(2)`
`2T^(2)=T_(1)^(2)-T_(2)^(2)`

ANSWER :C


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