1.

The time period of simple pendulum is T. When the length increases by 10 cm, its period is T_1. When the length is decreased by 10 cm, its period is T. Then the relation between T, T_1 and T_2 is

Answer»

`2/(T^2) = 1/(T_1^2) + 1/(T_2^2)`
`2/(T^2) = 1/(T_1^2) - 1/(T_2^2)`
`2T^2= T_1^2 + T_2^2`
`2T^2 = T_1^2 - T_2^2`

ANSWER :C


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