1.

The time period of simple pendulum is 'T'. When the length increases by 10 cm, its period is T_(1). When the length is decreased by 10 cm, its period is T_(2). Then the relation between T, T_(2) and T_(2) is

Answer»

`(2)/(T^(2))= (1)/(T_(1)^(2))+ (1)/(T_(2)^(2))`
`(2)/(T^(2))= (1)/(T_(1)^(2))-(1)/(T_(2)^(2))`
`2T^(2)= T_(1)^(2)+ T_(2)^(2)`
`2T^(2)= T_(1)^(2)-T_(2)^(2)`

ANSWER :C


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