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The time required for the light to pass through a glass slab ( refractive index=1.5) of thickness u mm is (c=`3xx10^(8)ms^(-1)` speed of light in free space)A. `10^(-11)`sB. `2xx10^(-11)`sC. `2xx10^(11)`sD. `2xx10^(-5)`s |
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Answer» Correct Answer - B (b) we have `n_(a)c_(a)=n_(g)c_(g)` `n_(g)/n_(a)=c_a/c_g` `3/2=(3xx10^(8))/c_(g)` `c_(g)=2xx10^(8)` Time = `"Distance"/"Speed"` `t=(4xx10^(-3))/(2xx10^(8))` `t=2xx10^(-11)s` |
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