The time required to coat a metal surface of `80 cm^(2)` with `5 xx 10^(-3) cm` thick layer of silver (density `1.05 g cm^(-3)`) with the passage of `3A` current through a silver nitrate solution is:A. 1150 sB. 1250 sC. 1350 sD. 1450 s

The time required to coat a metal surface of `80 cm^(2)` with `5 xx 10

1.	The time required to coat a metal surface of `80 cm^(2)` with `5 xx 10^(-3) cm` thick layer of silver (density `1.05 g cm^(-3)`) with the passage of `3A` current through a silver nitrate solution is:A. 1150 sB. 1250 sC. 1350 sD. 1450 s
Answer» Correct Answer - B Vol. of Ag = `800 xx 5 xx 10^(-4) cm^(3)` . Mass of Ag = `V xx d = 0.4 xx 10.5 = 4.2` g `Ag^(+) + e^(-) to Ag`, 108 g Ag require , 96500 C , `therefore 4.2` g require = `(96500)/(108) xx 4.2 = 3753` C . Hence , `t = (Q)/(I) = (3753)/(3) = 1251` sec .

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The time required to coat a metal surface of `80 cm^(2)` with `5 xx 10^(-3) cm` thick layer of silver (density `1.05 g cm^(-3)`) with the passage of `3A` current through a silver nitrate solution is:A. 1150 sB. 1250 sC. 1350 sD. 1450 s

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