1.

The time required to deposit 90 g of Al from an electrolytic cell containing Al_(2)O_(3)by a current of 965 A (At.mass of Al = 27)

Answer»

20 min . 20 sec
16 min . 40 sec
40 min 20 sec
26 min

SOLUTION :W = 90 gm , i= 965 A , t = ? W = Zit `therefore t = (W)/(ZI)`
`Z = ("Eq. MASS")/(96500)`
for AL , Eq. mass `= (27)/(3) therefore Z = (27)/(3 xx 96500)`
`t = (90 xx 3 xx 96500)/(27 xx 965) = 1000` sec = 16 min . 40 sec


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