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The time required to deposit 90 g of Al from an electrolytic cell containing `Al_(2)O_(3) ` by a current of 965 A (At.mass of Al = 27)A. 20 min . 20 secB. 16 min . 40 secC. 40 min 20 secD. 26 min |
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Answer» Correct Answer - B W = 90 gm , i= 965 A , t = ? W = Zit `therefore t = (W)/(Zi)` `Z = ("Eq. mass")/(96500)` for Al , Eq. mass `= (27)/(3) therefore Z = (27)/(3 xx 96500)` `t = (90 xx 3 xx 96500)/(27 xx 965) = 1000` sec = 16 min . 40 sec |
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