1.

The time taken for 10% completion of a first order reaction is 20 mins. Then, for 19% completion, the reaction will take

Answer»

40 mins
60 mins
30 mins
50 mins

SOLUTION : `k = (2.303)/(20) log (100)/(90)`…(i)
`k=(2.303)/(x) log (100)/((100-19))`…(II)
On equating (i) and (ii), `x=(20(2-log81))/((2-log90))`=40 mins


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