 
                 
                InterviewSolution
 Saved Bookmarks
    				| 1. | The time taken for 10% completion of a first order reaction is 20 min . Then for 19% completion the reaction will take : | 
| Answer» 40 MINS  `k = (2.303)/(x) "log" (100)/(81)` since (i) = (II) `(2.303)/(20)"log" (100)/(90) = (2.303)/(x) "log" (100)/(81)` `x= (20 "log"(100)/(81))/("log" (100)/(90))` `= (20xx0.0915)/(0.046) = 40 ` min | |