1.

The time taken for an electron to complete one revolution in Bohr orbit of hydrogen atom is

Answer»

`(4m^(2)pir^(2))/(n^(2)h^(2))`
`(n^(2)h^(2))/(4mr^(2))`
`(4pi^(2)mr^(2))/(NH)`
`(nh)/(4pi^(2)mr^(2))`

Solution :We KNOW according to Bohr.s theory `mvr=(nh)/(2pi)`
`rArrv=(nh)/(2pimr)`
`therefore` Time required for one complete REVOLUTION,
`T=(2pir)/V=(2pir)/(nh)2pimr=(4pi^(2)mr^(2))/(nh)`


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