The time taken for diffusion of CO_(2(g)) is twice than that of unknown gas of same volume under identical condition. Calculate the molecular weight of unknown gas. (C = 12, O = 16).

The time taken for diffusion of CO_(2(g)) is twice than that of unknow

1.	The time taken for diffusion of CO_(2(g)) is twice than that of unknown gas of same volume under identical condition. Calculate the molecular weight of unknown gas. (C = 12, O = 16).
Answer» 11 gm/mol 176 gm/mol 88 gm/mol 22 gm/mol Solution :`UNDERSET((t_(1)))("Unknown gas") "" underset((t_(2)))(CO_(2)" gas")` `(r_(1))/(r_(2))=(V_(1)t_(2))/(V_(2)t_(1))=SQRT((M_(2))/(M_(1)))` `V_(1)=V_(2) "" t_(2)=2t_(1)` `(2t_(1))/(t_(1))=sqrt((44)/(M_(1)))` `therefore 2=sqrt((44)/(M_(1)))` `therefore 4=(44)/(M_(1)) "" therefore M_(1)=11" gm mole"^(-1)`