1.

The titanium (atomic number 22) compound that does not exist isA. TiOB. `TiO_(2)`C. `K_(2)TiF_(6)`D. `TiCl_(3)`

Answer» Correct Answer - C
`Ti(Z=22)` has configuration
`[Ar]^(18)3d^(2)4s^(2)` ltbr It can show oxidation states of +1,+2,+3,+4 In `K_(2)TiO_(4)` : oxidation state of Ti=+6 Therefore, it does not exist.


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