The top of insulated cylindrical container is covered by a disc having emissivity 0.6 and thickness 1 cm. The temperature is maintained by circulating oil as shown in figure. If temperature of upper surface of disc is 127∘ Cand temperature of surrounding is 27∘ C, then the radiation loss to the surroundings will be (Take σ=173×10−8W/m2K4)

The top of insulated cylindrical container is covered by a disc having

1.	The top of insulated cylindrical container is covered by a disc having emissivity 0.6 and thickness 1 cm. The temperature is maintained by circulating oil as shown in figure. If temperature of upper surface of disc is 127∘ Cand temperature of surrounding is 27∘ C, then the radiation loss to the surroundings will be (Take σ=173×10−8W/m2K4)
Answer» The top of insulated cylindrical container is covered by a disc having emissivity 0.6 and thickness 1 cm. The temperature is maintained by circulating oil as shown in figure. If temperature of upper surface of disc is $127^{\circ}$ Cand temperature of surrounding is $27^{\circ}$ C, then the radiation loss to the surroundings will be (Take $σ = \frac{17}{3} \times 10^{- 8} W / m^{2} K^{4}$ )

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