The total cost of 8 apples and 5 oranges is Rs 92 and the total cost o

1.	The total cost of 8 apples and 5 oranges is Rs 92 and the total cost of 5 apples and 8 oranges is Rs 77, Find the cost of 2 oranges and 3 apples. (a) Rs 30 (b) Rs 35 (c) Rs 38 (d) Rs 70
Answer» (b) Rs 35 Let the cost of one apple and one orange be Rs x and Rs y respectively. Then, according to the given question, 8x + 5y = 92 ........(i) 5x + 8y = 77 .........(ii) Multiplying eqn (i) by 5 and eqn (ii) by 8, we get 40x + 25y = 460 ….....(iii) 40x + 64y = 616 …....(iv) Subtracting eqn (iii) from eqn (iv), 39y = 156 \(\Rightarrow\) y = \(\frac{156}{39}\) = 4 From (i) putting the value of y, we get 8x + 20 = 92 \(\Rightarrow\) 8x = 72 \(\Rightarrow\)x = 9 \(\therefore\) Cost of 2 oranges and 3 apples = 2 × Rs 4 + 3 × Rs 9 = Rs 8 + Rs 27 = Rs 35.

The total cost of 8 apples and 5 oranges is Rs 92 and the total cost of 5 apples and 8 oranges is Rs 77, Find the cost of 2 oranges and 3 apples. (a) Rs 30 (b) Rs 35 (c) Rs 38 (d) Rs 70

Answer»

(b) Rs 35

Let the cost of one apple and one orange be Rs x

and Rs y respectively.

Then, according to the given question,

8x + 5y = 92 ........(i)

5x + 8y = 77 .........(ii)

Multiplying eqn (i) by 5 and eqn (ii) by 8, we get

40x + 25y = 460 ….....(iii)

40x + 64y = 616 …....(iv)

Subtracting eqn (iii) from eqn (iv),

39y = 156

\(\Rightarrow\) y = \(\frac{156}{39}\) = 4

From (i) putting the value of y, we get

8x + 20 = 92

\(\Rightarrow\) 8x = 72 \(\Rightarrow\)x = 9

\(\therefore\) Cost of 2 oranges and 3 apples

= 2 × Rs 4 + 3 × Rs 9 = Rs 8 + Rs 27 = Rs 35.